PART 8：\(\int {\sin Ax\cos Bx\;dx} \)積分(04：50)

這類題型只要熟練積化和差公式便可容易解出
\(\sin Ax\cos Bx = \frac{1}{2}\left[ {\sin (A + B)x + \sin (A - B)x} \right]\)
\(\cos Ax\cos Bx = \frac{1}{2}\left[ {\cos (A + B)x + \cos (A - B)x} \right]\) \(\sin Ax\sin Bx = \frac{1}{2}\left[ {\cos (A - B)x - \cos (A + B)x} \right]\)